STEREOCHEMISTRY
Intent and Purpose
Stereochemistry is the study of the static and dynamic aspects of the
three-dimensional shapes of molecules. It has long provided a foundation for
understanding structure and reactivity. At the same time, stereochemistry
constitutes an intrinsically interesting research field in itsownright. Many chemists
find this area of study fascinating due simply to the aesthetic beauty
associated with chemical structures, and the intriguing ability to combine the
fields of geometry, topology, and chemistry in the study of three-dimensional
shapes. In addition, there are extremely important practical ramifications of
stereochemistry. Nature is inherently chiral because the building blocks of
life (_-amino acids, nucleotides, and sugars) are chiral and appear in nature
in enantiomerically pure forms. Hence, any substances created by humankind to
interact with or modify nature are interacting with a chiral environment. This
is an important issue for bioorganic chemists, and a practical issue for
pharmaceutical chemists. The Food and Drug Administration (FDA) now requires
that drugs be produced in enantiomerically pure forms, or that rigoroustests be
performed to ensure that both enantiomers are safe.
DRAWING STEREOCHEMICAL
STRUCTURES
Structural diagrams which depict stereochemistry must be prepared with
extra care to ensure there is no ambiguity. The ability to proficiently
draw and read such structures requires some practice with reference to 3D
molecular models. Some simple "do's" and "don'ts" of the
art of stereochemical drawing are illustrated below.
In general, the molecules are presented in some kind of perspective
drawing, based on the idea that the four substituents of a tetrahedral center
can be divided into two pairs, laying in mutually perpendicular planes.
Most often the center and two of such substituents are shown in the plane of
the drawing (i.e. the plane of the drawing surface) and their bonds are
depicted as plain lines ( ).
Bonds to the other two substituents are shown with different symbols. Bonds
to atoms above the plane of the drawing (coming out, toward the viewer) are
shown with a bold wedge ( ), with the narrow end of the wedge
starting at the stereogenic center. As an alternative bald bar bonds
( ) are used.
Bonds to atoms below the plane (going in, away from the viewer) are shown
with hash wedges ( ). There are two separate
conventions in use. In the American usage the narrow edge points to the
central atom, while in the European convention, the wide edge points to the
central atom. As an alternative, a bar of hash lines ( ) is used. A broken line ( ) or an open wedge ( ) can also be found in some drawings,
but their usage is discouraged
At this point you should
know that a carbon has four bonds. You may be drawing a carbon with four single
bonds that looks like this.
However, in reality, a
carbon with four single bonds is not as planar (flat) as the picture implies.
Instead the structure is more three-dimensional and looks like the
picture below:
Notice that the Bromine
(Br) and the methyl group (CH3) are drawn with narrow solid lines. This means
that these two substituents attached to the center carbon are planar (meaning
flat against the page). Also notice that the hydrogen is drawn with a dotted
line wedge which means that the hydrogen (H) is going into the plane of the
paper. Finally, notice that the ethyl group (CH2CH3) is
drawn with a solid wedge which means that it is coming out of the plane of the
paper (towards you). From now on all carbons with four single bonds should be
drawn with this stereochemistry.
A carbon with four
single bonds has four different substituents attached to it. If the carbon has
four different things attached to it, the carbon is called a stereogenic
center or chiral center. Often these two terms are used interchangeably,
however, we will be using the term stereogenic center for the rest of
this section. Let's look at two molecules below to make sure that you
understand.
Notice that molecule (A)
does not have any carbons with four different things attached to it (even the
center carbon has two methyl groups attached to it). Therefore, it does not
have a stereogenic center. However, let's look at molecule (B). Notice that the
center carbon has four different things attached to it. It denotes a
stereogenic center.
Once you are able to
locate a stereogenic center it is important to note that a molecule with at
least one stereogenic center on it is called an optically active
molecule. This means that if you take the molecule and put it into a beaker and
shine plane polarized light (just think of it like a flashlight) onto it, the
light will not come straight out the other end.
A molecule without any
stereogenic centers in it (not optically active):
Enantiomers
The next term that you
are responsible for learning is enantiomers. The formal definition of
enantiomers is as follows: Enantiomers are nonsuperimposable, mirror images.
Most basic organic chemistry textbooks will give you this defintion. However,
sometimes this definition becomes a bit confusing when you need to identify a
pair of enantiomers on an exam. Therefore, I will give you a more informal
definition to use.
Enantiomers: Two molecules, each having a stereogenic center
with the same four things attached to the carbon, except that one molecule's
stereogenic center is "R" and the other molecules stereogenic center
is "S". Let's look at an example!
(R) (S)
Notice that both
molecules have the same four things attached to the central carbon. Each carbon
has a hydrogen on it, a chlorine, an ethyl group, and a methyl group. However,
if you calculate the configuration of the stereogenic center you will see that
one molecule is "R" and the other one is "S". Therefore,
these two molecules are enantiomers.
A Racemic Mixture
The next term you are responsible for is a racemic
mixture. The formal definition of a racemic mixture is a mixture of enantiomers
in equal amounts. For example, let's look at the two molecules below.
(R) (S)
Notice that we
have 45 grams of each molecule which means that we have two enantiomers in
equal amounts. Therefore, we have a racemic mixture.
The "R"
molecule will cause the light in one direction and the "S" molecule
will cause the light to bend in the other direction. Because the two molecules
are present in equal amounts they will cancel one another out and the light
will come out of the other side of the beaker straight (as seen above).
Therefore, even though each molecule in a racemic mixture is optically active,
the racemic mixture is not optically active and therefore will not bend the
light.
Fischer Projection
Formulas
The
problem of drawing three-dimensional configurations on a two-dimensional
surface, such as a piece of paper, has been a long-standing concern of
chemists. The wedge and hatched line notations we have been using are
effective, but can be troublesome when applied to compounds having many chiral
centers. As part of his Nobel Prize-winning research on carbohydrates, the
great German chemist Emil Fischer,
devised a simple notation that is still widely used. In a Fischer projection
drawing, the four bonds to a chiral carbon make a cross with the carbon atom at
the intersection of the horizontal and vertical lines. The two horizontal bonds
are directed toward the viewer (forward of the stereogenic carbon). The two
vertical bonds are directed behind the central carbon (away from the viewer).
Since this is not the usual way in which we have viewed such structures, the
following diagram shows how a stereogenic carbon positioned in the common
two-bonds-in-a-plane orientation ( x–C–y define the reference plane ) is
rotated into the Fischer projection orientation (the far right formula). When
writing Fischer projection formulas it is important to remember these
conventions. Since the vertical bonds extend away from the viewer and the
horizontal bonds toward the viewer, a Fischer structure may only be turned by
180º within the plane, thus maintaining this relationship. The structure
must not be flipped over or rotated by 90º.
A model of the preceding diagram may be examined by .
In the
above diagram, if x = CO2H, y = CH3, a = H & b = OH,
the resulting formula describes (R)-(–)-lactic acid. The mirror-image
formula, where x = CO2H, y = CH3, a = OH & b = H,
would, of course, represent (S)-(+)-lactic acid.
Using
the Fischer projection notation, the stereoisomers of
2-methylamino-1-phenylpropanol are drawn in the following manner. Note that it
is customary to set the longest carbon chain as the vertical bond assembly.
The
usefulness of this notation to Fischer, in his carbohydrate studies, is evident
in the following diagram. There are eight stereoisomers of
2,3,4,5-tetrahydroxypentanal, a group of compounds referred to as the
aldopentoses. Since there are three chiral centers in this constitution, we
should expect a maximum of 23 stereoisomers. These eight
stereoisomers consist of four sets of enantiomers. If the configuration at C-4
is kept constant (R in the examples shown here), the four stereoisomers
that result will be diastereomers. Fischer formulas for these isomers,
which Fischer designated as the "D"-family, are shown in the diagram.
Each of these compounds has an enantiomer, which is a member of the
"L"-family so, as expected, there are eight stereoisomers in all.
Determining whether a chiral carbon is R or S may seem difficult when using
Fischer projections, but it is actually quite simple. If the lowest priority
group (often a hydrogen) is on a vertical bond, the configuration is given
directly from the relative positions of the three higher-ranked substituents.
If the lowest priority group is on a horizontal bond, the positions of the
remaining groups give the wrong answer (you are in looking at the configuration
from the wrong side), so you simply reverse it.
The
aldopentose structures drawn above are all diastereomers. A more selective
term, epimer, is used to designate diastereomers that differ in
configuration at only one chiral center. Thus, ribose and arabinose are epimers
at C-2, and arabinose and lyxose are epimers at C-3. However, arabinose and
xylose are not epimers, since their configurations differ at both C-2 and C-3.
Diastereomers
Diastereomers (sometimes called diastereoisomers) are stereoisomers
that are not enantiomers. Diastereomerism occurs when two or
more stereoisomers of a compound have different configurations at one or more
(but not all) of the equivalent (related) stereocenters
and are not mirror images of each other. When two diastereoisomers
differ from each other at only one stereocenter they are epimers. Each
stereocenter gives rise to two different configurations and thus increases the
number of stereoisomers by a factor of two.
Diastereomers differ from enantiomers in that the latter
are pairs of stereoisomers that differ in all stereocenters and are therefore
mirror images of one another. Enantiomers of a compound with more than one
stereocenter are also diastereomers of the other stereoisomers of that compound
that are not their mirror image. Diastereomers have different physical
properties (unlike enantiomers) and different chemical reactivity.
Cis-trans isomerism and conformational isomerism are also forms of
diastereomerism.
Diastereoselectivity is the preference for the formation of
one or more than one diastereomer over the other in an organic
reaction.
Erythro / threo
Two common prefixes used to distinguish
diastereomers are threo and erythro (which correspond to the more
intuitive syn and anti labels, respectively). When drawn in the Fischer projection the erythro isomer has two
identical substituents on the same side and the threo isomer has them on
opposite sides.When drawn as a zig-zag chain, the erythro isomer has two
identical substituents on different sides of the plane (anti). The names are
derived from the diastereomeric aldoses erythrose
(a syrup) and threose
(melting point 126 °C).
Another threo compound is threonine,
one of the essential amino acids. The erythro diastereomer is called allo-threonine.
L-Threonine
(2S,3R) and D-Threonine (2R,3S)
|
L-allo-Threonine
(2S,3S) and D-allo-Threonine (2R,3R)
|
Achiral Diastereomers
(meso-Compounds)
The
chiral centers in the preceding examples have all been different, one from
another. In the case of 2,3-dihydroxybutanedioic acid, known as tartaric acid,
the two chiral centers have the same four substituents and are equivalent. As a
result, two of the four possible stereoisomers of this compound are identical
due to a plane of symmetry, so there are only three stereoisomeric tartaric
acids. Two of these stereoisomers are enantiomers and the third is an achiral
diastereomer, called a meso compound. Meso compounds are achiral
(optically inactive) diastereomers of chiral stereoisomers. Investigations of
isomeric tartaric acid salts, carried out by Louis Pasteur in the mid 19th century, were
instrumental in elucidating some of the subtleties of stereochemistry.
Some physical properties of the isomers of tartaric acid are given in the following table.
Some physical properties of the isomers of tartaric acid are given in the following table.
(+)-tartaric acid:
|
[α]D = +13º
|
m.p. 172 ºC
|
(–)-tartaric acid:
|
[α]D = –13º
|
m.p. 172 ºC
|
meso-tartaric acid:
|
[α]D = 0º
|
m.p. 140 ºC
|
Fischer
projection formulas provide a helpful view of the configurational relationships
within the structures of these isomers. In the following illustration a mirror
line is drawn between formulas that have a mirror-image relationship. In
demonstrating the identity of the two meso-compound formulas, remember that a
Fischer projection formula may be rotated 180º in the plane.
why in a Racemic Mixture The "R" molecule will cause the light in one direction and the "S" molecule will cause the light to bend in the other direction? and what would happen if that happened was the opposite?whether it can?
BalasHapus